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Suppose we want to find
$$
\int_0^\infty f(x) exp(-x) dx
$$
But we are not given
x, w= FastGaussQuadrature.gausslaguerre(150)
g = x -> sin(x)*exp(-x)
dot(w, g.(x).*exp.(x)) ≈ 0.5 # trueGreat!
Uh oh:
x, w= FastGaussQuadrature.gausslaguerre(200)
g = x -> sin(x)*exp(-x)
dot(w, g.(x).*exp.(x)) |> isnan # trueIf we had a weightedgausslaguerre that returned w.*exp.(x) instead of w everything would be perfect. I suspect it's just as easy to calculate these weights as standard Gauss–Laguerre.
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